@Guess Who I hope you get better!
"The Young Man and the Monopoly Sea"
@Plank Sinatra@Write@Crimmy@Eklispe@Lazo@Forsythe@HereComesTheSnow
"The Young Man and the Monopoly Sea"
@Plank Sinatra@Write@Crimmy@Eklispe@Lazo@Forsythe@HereComesTheSnow
For a Newtonian particle, with p = mu, the momentum is directly proportional to the velocity. The relativistic expression for momentum agrees with the Newtonian value if u ≪ c, but p approaches ∞ as u -> c.
For a Newtonian particle, with p = mu, the momentum is directly proportional to the velocity. The relativistic expression for momentum agrees with the Newtonian value if u ≪ c, but p approaches ∞ as u -> c.
<Snipped quote by Crimmy>
I don't know all the variables but I think it describes what happens if something moves faster than the speed of light. Do I have that right?
For a Newtonian particle, with p = mu, the momentum is directly proportional to the velocity. The relativistic expression for momentum agrees with the Newtonian value if u ≪ c, but p approaches ∞ as u -> c.
<Snipped quote by Prince of Seraphs>
According to Newtonian mechanics, the momentum of a particle is equal to its mass multiplied by its velocity. Momentum is also a conserved quantity, which is true in all reference frames related by Galilean velocity transformations. However, the Galilean transformations are inconsistent with relativity. Say you're moving at 0.9c with respect to Earth, and then you shoot out an object that moves at 0.95c with respect to you; you'd expect the velocity of the object to be 1.85c with respect to the Earth, which is impossible because c, the speed of light in a vacuum, is the speed limit in all reference frames. But because you can't just throw the conservation of momentum out the window, however, you have to account for why it still works at significant fractions of c. It's an alright approximation when velocity "u" is small, but when you get big it starts going wonky. Instead, you'll have to use the "true time" measured by the particle itself.
You'll have to use the Lorentz transformations (except using the velocity of the particle rather than the reference frame) to get relativistic momentum.
@Crimson Raven C is the same in all reference frames.
Time intervals will differ between reference frames.
What's even more interesting is, that according to the theory, if you were to go past c, time would move backwards from your point of view and people would observe two of you.
Gotta change his name to Impulse.
Except Bart's still fucking dead.
<Snipped quote by Crimmy>
Bart Allen died?